Base | Representation |
---|---|
bin | 1110110010000… |
… | …11111000100111 |
3 | 22122100100202211 |
4 | 13121003320213 |
5 | 223221310043 |
6 | 20145544251 |
7 | 3034032154 |
oct | 731037047 |
9 | 278310684 |
10 | 124010023 |
11 | 64000625 |
12 | 35645087 |
13 | 1c8cc217 |
14 | 1268122b |
15 | ad48a9d |
hex | 7643e27 |
124010023 has 4 divisors (see below), whose sum is σ = 124481808. Its totient is φ = 123538240.
The previous prime is 124010021. The next prime is 124010041. The reversal of 124010023 is 320010421.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 320010421 = 367 ⋅871963.
It is a cyclic number.
It is not a de Polignac number, because 124010023 - 21 = 124010021 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 124009985 and 124010012.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (124010021) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 235498 + ... + 236023.
It is an arithmetic number, because the mean of its divisors is an integer number (31120452).
Almost surely, 2124010023 is an apocalyptic number.
124010023 is a deficient number, since it is larger than the sum of its proper divisors (471785).
124010023 is an equidigital number, since it uses as much as digits as its factorization.
124010023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 471784.
The product of its (nonzero) digits is 48, while the sum is 13.
The square root of 124010023 is about 11135.9787625516. The cubic root of 124010023 is about 498.6765306151.
Adding to 124010023 its reverse (320010421), we get a palindrome (444020444).
The spelling of 124010023 in words is "one hundred twenty-four million, ten thousand, twenty-three".
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