Search a number
-
+
1240110125146 = 2620055062573
BaseRepresentation
bin10010000010111100010…
…100101101000001011010
311101112221101222120210001
4102002330110231001122
5130304221143001041
62345410531443214
7155411041066264
oct22027424550132
94345841876701
101240110125146
11438a22921852
1218041245650a
138cc32417579
14440435a0b34
15223d11c7131
hex120bc52d05a

1240110125146 has 4 divisors (see below), whose sum is σ = 1860165187722. Its totient is φ = 620055062572.

The previous prime is 1240110125131. The next prime is 1240110125147. The reversal of 1240110125146 is 6415210110421.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 1207262550025 + 32847575121 = 1098755^2 + 181239^2 .

It is not an unprimeable number, because it can be changed into a prime (1240110125147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 310027531285 + ... + 310027531288.

Almost surely, 21240110125146 is an apocalyptic number.

1240110125146 is a deficient number, since it is larger than the sum of its proper divisors (620055062576).

1240110125146 is an equidigital number, since it uses as much as digits as its factorization.

1240110125146 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 620055062575.

The product of its (nonzero) digits is 1920, while the sum is 28.

Adding to 1240110125146 its reverse (6415210110421), we get a palindrome (7655320235567).

The spelling of 1240110125146 in words is "one trillion, two hundred forty billion, one hundred ten million, one hundred twenty-five thousand, one hundred forty-six".

Divisors: 1 2 620055062573 1240110125146