12401103314121 has 8 divisors (see below), whose sum is σ = 16538714297280. Its totient is φ = 8265447270192.

The previous prime is 12401103314081. The next prime is 12401103314137. The reversal of 12401103314121 is 12141330110421.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 12401103314121 - 2⁹ = 12401103313609 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12401103314091 and 12401103314100.

It is not an unprimeable number, because it can be changed into a prime (12401103314921) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 488720005 + ... + 488745378.

It is an arithmetic number, because the mean of its divisors is an integer number (2067339287160).

Almost surely, 2^{12401103314121} is an apocalyptic number.

It is an amenable number.

12401103314121 is a deficient number, since it is larger than the sum of its proper divisors (4137610983159).

12401103314121 is an equidigital number, since it uses as much as digits as its factorization.

12401103314121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 977469615.

The product of its (nonzero) digits is 576, while the sum is 24.

Adding to 12401103314121 its reverse (12141330110421), we get a palindrome (24542433424542).

The spelling of 12401103314121 in words is "twelve trillion, four hundred one billion, one hundred three million, three hundred fourteen thousand, one hundred twenty-one".