Base | Representation |
---|---|
bin | 11100001100100110100010… |
… | …110011000100010100001111 |
3 | 121021002100220020212121220211 |
4 | 130030212202303010110033 |
5 | 112223300141420032143 |
6 | 1115430003113223251 |
7 | 35056344110661136 |
oct | 3414464263042417 |
9 | 537070806777824 |
10 | 124011322033423 |
11 | 365719a73570a0 |
12 | 11aaa284a01b27 |
13 | 54272a9a93666 |
14 | 228a273d4a91d |
15 | e50c445b249d |
hex | 70c9a2cc450f |
124011322033423 has 4 divisors (see below), whose sum is σ = 135285078581928. Its totient is φ = 112737565484920.
The previous prime is 124011322033387. The next prime is 124011322033433. The reversal of 124011322033423 is 324330223110421.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-124011322033423 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (124011322033433) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5636878274236 + ... + 5636878274257.
It is an arithmetic number, because the mean of its divisors is an integer number (33821269645482).
Almost surely, 2124011322033423 is an apocalyptic number.
124011322033423 is a deficient number, since it is larger than the sum of its proper divisors (11273756548505).
124011322033423 is a wasteful number, since it uses less digits than its factorization.
124011322033423 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11273756548504.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 124011322033423 its reverse (324330223110421), we get a palindrome (448341545143844).
The spelling of 124011322033423 in words is "one hundred twenty-four trillion, eleven billion, three hundred twenty-two million, thirty-three thousand, four hundred twenty-three".
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