Base | Representation |
---|---|
bin | 1011010001110101111000… |
… | …1101110001100001001001 |
3 | 1121220112112112221011101201 |
4 | 2310131132031301201021 |
5 | 3111140024210040203 |
6 | 42213002113344201 |
7 | 2416645042261660 |
oct | 264353615614111 |
9 | 47815475834351 |
10 | 12401151252553 |
11 | 3a51331648298 |
12 | 1483514568061 |
13 | 6bc5676b514b |
14 | 30c30ca21dd7 |
15 | 1678b0925e1d |
hex | b475e371849 |
12401151252553 has 32 divisors (see below), whose sum is σ = 15415886013440. Its totient is φ = 9737832000960.
The previous prime is 12401151252533. The next prime is 12401151252557. The reversal of 12401151252553 is 35525215110421.
12401151252553 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 12401151252553 - 25 = 12401151252521 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (37).
It is not an unprimeable number, because it can be changed into a prime (12401151252557) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 6928083 + ... + 8532328.
It is an arithmetic number, because the mean of its divisors is an integer number (481746437920).
Almost surely, 212401151252553 is an apocalyptic number.
It is an amenable number.
12401151252553 is a deficient number, since it is larger than the sum of its proper divisors (3014734760887).
12401151252553 is a wasteful number, since it uses less digits than its factorization.
12401151252553 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15460637.
The product of its (nonzero) digits is 60000, while the sum is 37.
Adding to 12401151252553 its reverse (35525215110421), we get a palindrome (47926366362974).
The spelling of 12401151252553 in words is "twelve trillion, four hundred one billion, one hundred fifty-one million, two hundred fifty-two thousand, five hundred fifty-three".
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