Base | Representation |
---|---|
bin | 1011010001110110001100… |
… | …1011000111011101000111 |
3 | 1121220112202100110121221101 |
4 | 2310131203023013131013 |
5 | 3111140212004121210 |
6 | 42213014244400531 |
7 | 2416650102340654 |
oct | 264354313073507 |
9 | 47815670417841 |
10 | 12401234442055 |
11 | 3a513745a7848 |
12 | 14835383a6147 |
13 | 6bc57b9c11c4 |
14 | 30c319ab8c2b |
15 | 1678b7da9a3a |
hex | b47632c7747 |
12401234442055 has 8 divisors (see below), whose sum is σ = 14881516578000. Its totient is φ = 9920964055296.
The previous prime is 12401234441923. The next prime is 12401234442101. The reversal of 12401234442055 is 55024443210421.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 12401234442055 - 29 = 12401234441543 is a prime.
It is a super-2 number, since 2×124012344420552 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 418905 + ... + 4997794.
It is an arithmetic number, because the mean of its divisors is an integer number (1860189572250).
Almost surely, 212401234442055 is an apocalyptic number.
12401234442055 is a deficient number, since it is larger than the sum of its proper divisors (2480282135945).
12401234442055 is an equidigital number, since it uses as much as digits as its factorization.
12401234442055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5874593.
The product of its (nonzero) digits is 153600, while the sum is 37.
Adding to 12401234442055 its reverse (55024443210421), we get a palindrome (67425677652476).
The spelling of 12401234442055 in words is "twelve trillion, four hundred one billion, two hundred thirty-four million, four hundred forty-two thousand, fifty-five".
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