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12401315101555 = 514951533230363
BaseRepresentation
bin1011010001110110011111…
…1110110011101101110011
31121220112221222020112222021
42310131213332303231303
53111140343131222210
642213030245252311
72416652102051602
oct264354776635563
947815858215867
1012401315101555
113a51406089496
12148355b404097
136bc592622813
1430c3266b3a39
151678beeddbda
hexb4767fb3b73

12401315101555 has 16 divisors (see below), whose sum is σ = 14984366450400. Its totient is φ = 9852552414208.

The previous prime is 12401315101519. The next prime is 12401315101603. The reversal of 12401315101555 is 55510151310421.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12401315101555 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 12401315101555.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2223804 + ... + 5454166.

It is an arithmetic number, because the mean of its divisors is an integer number (936522903150).

Almost surely, 212401315101555 is an apocalyptic number.

12401315101555 is a deficient number, since it is larger than the sum of its proper divisors (2583051348845).

12401315101555 is a wasteful number, since it uses less digits than its factorization.

12401315101555 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3235670.

The product of its (nonzero) digits is 15000, while the sum is 34.

Adding to 12401315101555 its reverse (55510151310421), we get a palindrome (67911466411976).

The spelling of 12401315101555 in words is "twelve trillion, four hundred one billion, three hundred fifteen million, one hundred one thousand, five hundred fifty-five".

Divisors: 1 5 149 745 5153 25765 767797 3230363 3838985 16151815 481324087 2406620435 16646060539 83230302695 2480263020311 12401315101555