12401343335 has 8 divisors (see below), whose sum is σ = 15020693136. Its totient is φ = 9828353920.

The previous prime is 12401343307. The next prime is 12401343337. The reversal of 12401343335 is 53334310421.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 12401343335 - 2⁶ = 12401343271 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12401343298 and 12401343307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12401343337) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11589506 + ... + 11590575.

It is an arithmetic number, because the mean of its divisors is an integer number (1877586642).

Almost surely, 2^12401343335 is an apocalyptic number.

12401343335 is a deficient number, since it is larger than the sum of its proper divisors (2619349801).

12401343335 is a wasteful number, since it uses less digits than its factorization.

12401343335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23180193.

The product of its (nonzero) digits is 12960, while the sum is 29.

Adding to 12401343335 its reverse (53334310421), we get a palindrome (65735653756).

The spelling of 12401343335 in words is "twelve billion, four hundred one million, three hundred forty-three thousand, three hundred thirty-five".