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1240135453 = 19836431223
BaseRepresentation
bin100100111101010…
…1111011100011101
310012102112102000201
41021322233130131
510014433313303
6323020223501
742505656154
oct11172573435
93172472021
101240135453
1158702a137
122a739ab91
13169c0787b
14ba9ba59b
1573d1781d
hex49eaf71d

1240135453 has 16 divisors (see below), whose sum is σ = 1324270080. Its totient is φ = 1157957424.

The previous prime is 1240135451. The next prime is 1240135483. The reversal of 1240135453 is 3545310421.

It is a cyclic number.

It is not a de Polignac number, because 1240135453 - 21 = 1240135451 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1240135451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1013400 + ... + 1014622.

It is an arithmetic number, because the mean of its divisors is an integer number (82766880).

Almost surely, 21240135453 is an apocalyptic number.

It is an amenable number.

1240135453 is a deficient number, since it is larger than the sum of its proper divisors (84134627).

1240135453 is a wasteful number, since it uses less digits than its factorization.

1240135453 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1968.

The product of its (nonzero) digits is 7200, while the sum is 28.

The square root of 1240135453 is about 35215.5569741556. The cubic root of 1240135453 is about 1074.3761884300.

Adding to 1240135453 its reverse (3545310421), we get a palindrome (4785445874).

The spelling of 1240135453 in words is "one billion, two hundred forty million, one hundred thirty-five thousand, four hundred fifty-three".

Divisors: 1 19 83 643 1223 1577 12217 23237 53369 101509 786389 1014011 1928671 14941391 65270287 1240135453