1240143320203 has 4 divisors (see below), whose sum is σ = 1240145620560. Its totient is φ = 1240141019848.

The previous prime is 1240143320153. The next prime is 1240143320209. The reversal of 1240143320203 is 3020233410421.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1240143320203 - 2¹³ = 1240143312011 is a prime.

It is a super-2 number, since 2×1240143320203² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1240143320209) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 143553 + ... + 1581421.

It is an arithmetic number, because the mean of its divisors is an integer number (310036405140).

Almost surely, 2^{1240143320203} is an apocalyptic number.

1240143320203 is a deficient number, since it is larger than the sum of its proper divisors (2300357).

1240143320203 is an equidigital number, since it uses as much as digits as its factorization.

1240143320203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2300356.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 1240143320203 its reverse (3020233410421), we get a palindrome (4260376730624).

The spelling of 1240143320203 in words is "one trillion, two hundred forty billion, one hundred forty-three million, three hundred twenty thousand, two hundred three".