Base | Representation |
---|---|
bin | 1011010001111001011110… |
… | …0111100110011101101101 |
3 | 1121220122000200010021111220 |
4 | 2310132113213212131231 |
5 | 3111144012231334313 |
6 | 42213241435333553 |
7 | 2420010645250266 |
oct | 264362747463555 |
9 | 47818020107456 |
10 | 12402114324333 |
11 | 3a51786239388 |
12 | 1483742bb12b9 |
13 | 6bc68c0929c6 |
14 | 30c3a08b996d |
15 | 16791a260823 |
hex | b47979e676d |
12402114324333 has 8 divisors (see below), whose sum is σ = 16540404480000. Its totient is φ = 8265950192448.
The previous prime is 12402114324289. The next prime is 12402114324371. The reversal of 12402114324333 is 33342341120421.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 12402114324333 - 214 = 12402114307949 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12402114324294 and 12402114324303.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12402114324833) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 531492333 + ... + 531515666.
It is an arithmetic number, because the mean of its divisors is an integer number (2067550560000).
Almost surely, 212402114324333 is an apocalyptic number.
It is an amenable number.
12402114324333 is a deficient number, since it is larger than the sum of its proper divisors (4138290155667).
12402114324333 is a wasteful number, since it uses less digits than its factorization.
12402114324333 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1063011891.
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 12402114324333 its reverse (33342341120421), we get a palindrome (45744455444754).
The spelling of 12402114324333 in words is "twelve trillion, four hundred two billion, one hundred fourteen million, three hundred twenty-four thousand, three hundred thirty-three".
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