Base | Representation |
---|---|
bin | 10111000110011110… |
… | …01011110110100011 |
3 | 1012000100012022122022 |
4 | 23203033023312203 |
5 | 200344444441311 |
6 | 5410401132055 |
7 | 616225115240 |
oct | 134317136643 |
9 | 35010168568 |
10 | 12402343331 |
11 | 5294888124 |
12 | 24a162a02b |
13 | 12286168c1 |
14 | 8592325c7 |
15 | 4c8c485db |
hex | 2e33cbda3 |
12402343331 has 8 divisors (see below), whose sum is σ = 14414346240. Its totient is φ = 10450400328.
The previous prime is 12402343313. The next prime is 12402343333. The reversal of 12402343331 is 13334320421.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 12402343331 - 226 = 12335234467 is a prime.
It is a super-2 number, since 2×124023433312 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 12402343331.
It is not an unprimeable number, because it can be changed into a prime (12402343333) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15014531 + ... + 15015356.
It is an arithmetic number, because the mean of its divisors is an integer number (1801793280).
Almost surely, 212402343331 is an apocalyptic number.
12402343331 is a deficient number, since it is larger than the sum of its proper divisors (2012002909).
12402343331 is an equidigital number, since it uses as much as digits as its factorization.
12402343331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30029953.
The product of its (nonzero) digits is 5184, while the sum is 26.
Adding to 12402343331 its reverse (13334320421), we get a palindrome (25736663752).
The spelling of 12402343331 in words is "twelve billion, four hundred two million, three hundred forty-three thousand, three hundred thirty-one".
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