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12402343313 is a prime number
BaseRepresentation
bin10111000110011110…
…01011110110010001
31012000100012022121122
423203033023312101
5200344444441223
65410401132025
7616225115213
oct134317136621
935010168548
1012402343313
115294888108
1224a162a015
1312286168a9
148592325b3
154c8c485c8
hex2e33cbd91

12402343313 has 2 divisors, whose sum is σ = 12402343314. Its totient is φ = 12402343312.

The previous prime is 12402343277. The next prime is 12402343333. The reversal of 12402343313 is 31334320421.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6480733009 + 5921610304 = 80503^2 + 76952^2 .

It is a cyclic number.

It is not a de Polignac number, because 12402343313 - 212 = 12402339217 is a prime.

It is not a weakly prime, because it can be changed into another prime (12402343333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6201171656 + 6201171657.

It is an arithmetic number, because the mean of its divisors is an integer number (6201171657).

Almost surely, 212402343313 is an apocalyptic number.

It is an amenable number.

12402343313 is a deficient number, since it is larger than the sum of its proper divisors (1).

12402343313 is an equidigital number, since it uses as much as digits as its factorization.

12402343313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 26.

Adding to 12402343313 its reverse (31334320421), we get a palindrome (43736663734).

The spelling of 12402343313 in words is "twelve billion, four hundred two million, three hundred forty-three thousand, three hundred thirteen".