Search a number
-
+
124034113 = 719989041
BaseRepresentation
bin1110110010010…
…01110001000001
322122101120211001
413121021301001
5223223042423
620150252001
73034162330
oct731116101
9278346731
10124034113
1164017735
1235657001
131c90a188
1412689d17
15ad50cad
hex7649c41

124034113 has 8 divisors (see below), whose sum is σ = 142467200. Its totient is φ = 105779520.

The previous prime is 124034087. The next prime is 124034129. The reversal of 124034113 is 311430421.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 124034113 - 213 = 124025921 is a prime.

It is a super-2 number, since 2×1240341132 = 30768922375393538, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (124034153) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 43128 + ... + 45913.

It is an arithmetic number, because the mean of its divisors is an integer number (17808400).

Almost surely, 2124034113 is an apocalyptic number.

It is an amenable number.

124034113 is a deficient number, since it is larger than the sum of its proper divisors (18433087).

124034113 is an equidigital number, since it uses as much as digits as its factorization.

124034113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 89247.

The product of its (nonzero) digits is 288, while the sum is 19.

The square root of 124034113 is about 11137.0603392457. The cubic root of 124034113 is about 498.7088192413.

Adding to 124034113 its reverse (311430421), we get a palindrome (435464534).

It can be divided in two parts, 1240 and 34113, that added together give a palindrome (35353).

The spelling of 124034113 in words is "one hundred twenty-four million, thirty-four thousand, one hundred thirteen".

Divisors: 1 7 199 1393 89041 623287 17719159 124034113