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12403412002033 = 134492124963509
BaseRepresentation
bin1011010001111110010011…
…1101110110010011110001
31121220202101002221010122221
42310133210331312103301
53111204141433031113
642214014313201041
72420055053316223
oct264374475662361
947822332833587
1012403412002033
113a5229179a898
121483a45700181
136bc837b96930
1430c484d94413
1516799414298d
hexb47e4f764f1

12403412002033 has 8 divisors (see below), whose sum is σ = 13387270113000. Its totient is φ = 11423803819008.

The previous prime is 12403412002021. The next prime is 12403412002063. The reversal of 12403412002033 is 33020021430421.

It can be written as a sum of positive squares in 4 ways, for example, as 111365809 + 12403300636224 = 10553^2 + 3521832^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12403412002033 is a prime.

It is a super-2 number, since 2×124034120020332 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12403412001989 and 12403412002007.

It is not an unprimeable number, because it can be changed into a prime (12403412002063) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1062475918 + ... + 1062487591.

It is an arithmetic number, because the mean of its divisors is an integer number (1673408764125).

Almost surely, 212403412002033 is an apocalyptic number.

12403412002033 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

12403412002033 is a deficient number, since it is larger than the sum of its proper divisors (983858110967).

12403412002033 is a wasteful number, since it uses less digits than its factorization.

12403412002033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2124963971.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 12403412002033 its reverse (33020021430421), we get a palindrome (45423433432454).

The spelling of 12403412002033 in words is "twelve trillion, four hundred three billion, four hundred twelve million, two thousand, thirty-three".

Divisors: 1 13 449 5837 2124963509 27624525617 954108615541 12403412002033