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1240343240555 = 5454033546367
BaseRepresentation
bin10010000011001010001…
…101111101111101101011
311101120112122122002000002
4102003022031331331223
5130310210332144210
62345450020133215
7155416601406116
oct22031215757553
94346478562002
101240343240555
11439032472911
1218047853720b
138cc6b7c7893
144406652357d
15223e68c34a5
hex120ca37df6b

1240343240555 has 8 divisors (see below), whose sum is σ = 1488417891072. Its totient is φ = 992270590848.

The previous prime is 1240343240533. The next prime is 1240343240561. The reversal of 1240343240555 is 5550423430421.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1240343240555 - 28 = 1240343240299 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1996982 + ... + 2543348.

It is an arithmetic number, because the mean of its divisors is an integer number (186052236384).

Almost surely, 21240343240555 is an apocalyptic number.

1240343240555 is a deficient number, since it is larger than the sum of its proper divisors (248074650517).

1240343240555 is an equidigital number, since it uses as much as digits as its factorization.

1240343240555 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1000405.

The product of its (nonzero) digits is 288000, while the sum is 38.

Adding to 1240343240555 its reverse (5550423430421), we get a palindrome (6790766670976).

The spelling of 1240343240555 in words is "one trillion, two hundred forty billion, three hundred forty-three million, two hundred forty thousand, five hundred fifty-five".

Divisors: 1 5 454033 546367 2270165 2731835 248068648111 1240343240555