12404043314333 has 8 divisors (see below), whose sum is σ = 13861724679936. Its totient is φ = 11001368792800.

The previous prime is 12404043314309. The next prime is 12404043314389. The reversal of 12404043314333 is 33341334040421.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12404043314333 - 2¹⁴ = 12404043297949 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12404043314293 and 12404043314302.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12404063314333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 13751710541 + ... + 13751711442.

It is an arithmetic number, because the mean of its divisors is an integer number (1732715584992).

Almost surely, 2^{12404043314333} is an apocalyptic number.

It is an amenable number.

12404043314333 is a deficient number, since it is larger than the sum of its proper divisors (1457681365603).

12404043314333 is a wasteful number, since it uses less digits than its factorization.

12404043314333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 27503422035.

The product of its (nonzero) digits is 124416, while the sum is 35.

Adding to 12404043314333 its reverse (33341334040421), we get a palindrome (45745377354754).

The spelling of 12404043314333 in words is "twelve trillion, four hundred four billion, forty-three million, three hundred fourteen thousand, three hundred thirty-three".