Base | Representation |
---|---|
bin | 10111000110101101… |
… | …01100100100010011 |
3 | 1012000110220100121112 |
4 | 23203112230210103 |
5 | 200401000443324 |
6 | 5410511243535 |
7 | 616250625626 |
oct | 134326544423 |
9 | 35013810545 |
10 | 12404312339 |
11 | 5295a02501 |
12 | 24a22195ab |
13 | 1228b55bb3 |
14 | 8595c5dbd |
15 | 4c8ed6c0e |
hex | 2e35ac913 |
12404312339 has 4 divisors (see below), whose sum is σ = 12406449120. Its totient is φ = 12402175560.
The previous prime is 12404312329. The next prime is 12404312357. The reversal of 12404312339 is 93321340421.
12404312339 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12404312339 - 232 = 8109345043 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12404312329) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1059659 + ... + 1071300.
It is an arithmetic number, because the mean of its divisors is an integer number (3101612280).
Almost surely, 212404312339 is an apocalyptic number.
12404312339 is a deficient number, since it is larger than the sum of its proper divisors (2136781).
12404312339 is an equidigital number, since it uses as much as digits as its factorization.
12404312339 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2136780.
The product of its (nonzero) digits is 15552, while the sum is 32.
The spelling of 12404312339 in words is "twelve billion, four hundred four million, three hundred twelve thousand, three hundred thirty-nine".
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