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1240444113 = 3413481371
BaseRepresentation
bin100100111101111…
…1010110011010001
310012110010002102120
41021323322303101
510020023202423
6323031004453
742511413066
oct11173726321
93173102376
101240444113
11587220027
122a7509729
13169cb51cc
14baa5ac6d
1573d78ee3
hex49efacd1

1240444113 has 4 divisors (see below), whose sum is σ = 1653925488. Its totient is φ = 826962740.

The previous prime is 1240444087. The next prime is 1240444133. The reversal of 1240444113 is 3114440421.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1240444113 - 220 = 1239395537 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1240444133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 206740683 + ... + 206740688.

It is an arithmetic number, because the mean of its divisors is an integer number (413481372).

Almost surely, 21240444113 is an apocalyptic number.

It is an amenable number.

1240444113 is a deficient number, since it is larger than the sum of its proper divisors (413481375).

1240444113 is an equidigital number, since it uses as much as digits as its factorization.

1240444113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 413481374.

The product of its (nonzero) digits is 1536, while the sum is 24.

The square root of 1240444113 is about 35219.9391396408. The cubic root of 1240444113 is about 1074.4653156419.

Adding to 1240444113 its reverse (3114440421), we get a palindrome (4354884534).

The spelling of 1240444113 in words is "one billion, two hundred forty million, four hundred forty-four thousand, one hundred thirteen".

Divisors: 1 3 413481371 1240444113