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12405320213 = 111386750491
BaseRepresentation
bin10111000110110101…
…00010101000010101
31012000112210120011012
423203122202220111
5200401230221323
65410545022005
7616262324216
oct134332425025
935015716135
1012405320213
115296530760
1224a2624905
131229119880
148597a940d
154c9135678
hex2e36a2a15

12405320213 has 8 divisors (see below), whose sum is σ = 14574082656. Its totient is φ = 10410058800.

The previous prime is 12405320209. The next prime is 12405320281. The reversal of 12405320213 is 31202350421.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12405320213 - 22 = 12405320209 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12405320113) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 43375103 + ... + 43375388.

It is an arithmetic number, because the mean of its divisors is an integer number (1821760332).

Almost surely, 212405320213 is an apocalyptic number.

12405320213 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

12405320213 is a deficient number, since it is larger than the sum of its proper divisors (2168762443).

12405320213 is a wasteful number, since it uses less digits than its factorization.

12405320213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 86750515.

The product of its (nonzero) digits is 1440, while the sum is 23.

Adding to 12405320213 its reverse (31202350421), we get a palindrome (43607670634).

The spelling of 12405320213 in words is "twelve billion, four hundred five million, three hundred twenty thousand, two hundred thirteen".

Divisors: 1 11 13 143 86750491 954255401 1127756383 12405320213