124111214433 has 6 divisors (see below), whose sum is σ = 179271754194. Its totient is φ = 82740809616.

The previous prime is 124111214429. The next prime is 124111214497. The reversal of 124111214433 is 334412111421.

It is a happy number.

124111214433 is a `hidden beast` number, since 1 + 2 + 4 + 1 + 11 + 214 + 433 = 666.

It can be written as a sum of positive squares in only one way, i.e., 118505997009 + 5605217424 = 344247^2 + 74868^2 .

It is not a de Polignac number, because 124111214433 - 2² = 124111214429 is a prime.

It is a super-2 number, since 2×124111214433² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 124111214397 and 124111214406.

It is not an unprimeable number, because it can be changed into a prime (124111215433) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 6895067460 + ... + 6895067477.

It is an arithmetic number, because the mean of its divisors is an integer number (29878625699).

Almost surely, 2^124111214433 is an apocalyptic number.

It is an amenable number.

124111214433 is a deficient number, since it is larger than the sum of its proper divisors (55160539761).

124111214433 is a wasteful number, since it uses less digits than its factorization.

124111214433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13790134943 (or 13790134940 counting only the distinct ones).

The product of its digits is 2304, while the sum is 27.

Adding to 124111214433 its reverse (334412111421), we get a palindrome (458523325854).

The spelling of 124111214433 in words is "one hundred twenty-four billion, one hundred eleven million, two hundred fourteen thousand, four hundred thirty-three".