Base | Representation |
---|---|
bin | 10111000111100010… |
… | …00001001000101101 |
3 | 1012000221212220121212 |
4 | 23203301001020231 |
5 | 200404232243313 |
6 | 5411315204205 |
7 | 616363364342 |
oct | 134361011055 |
9 | 35027786555 |
10 | 12411212333 |
11 | 5299895583 |
12 | 24a45a6665 |
13 | 122a400730 |
14 | 85a4a07c9 |
15 | 4c98eb3a8 |
hex | 2e3c4122d |
12411212333 has 4 divisors (see below), whose sum is σ = 13365920988. Its totient is φ = 11456503680.
The previous prime is 12411212291. The next prime is 12411212339. The reversal of 12411212333 is 33321211421.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 33321211421 = 103 ⋅323506907.
It can be written as a sum of positive squares in 2 ways, for example, as 8102340169 + 4308872164 = 90013^2 + 65642^2 .
It is a cyclic number.
It is not a de Polignac number, because 12411212333 - 224 = 12394435117 is a prime.
It is a super-2 number, since 2×124112123332 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12411212299 and 12411212308.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12411212339) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 477354308 + ... + 477354333.
It is an arithmetic number, because the mean of its divisors is an integer number (3341480247).
Almost surely, 212411212333 is an apocalyptic number.
12411212333 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
12411212333 is a deficient number, since it is larger than the sum of its proper divisors (954708655).
12411212333 is an equidigital number, since it uses as much as digits as its factorization.
12411212333 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 954708654.
The product of its digits is 864, while the sum is 23.
Adding to 12411212333 its reverse (33321211421), we get a palindrome (45732423754).
The spelling of 12411212333 in words is "twelve billion, four hundred eleven million, two hundred twelve thousand, three hundred thirty-three".
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