Base | Representation |
---|---|
bin | 10111000111110001… |
… | …01011010101110101 |
3 | 1012001002122220220210 |
4 | 23203320223111311 |
5 | 200410241021323 |
6 | 5411430220033 |
7 | 616416426252 |
oct | 134370532565 |
9 | 35032586823 |
10 | 12413220213 |
11 | 529aa37089 |
12 | 24a51b4619 |
13 | 122a954624 |
14 | 85a864429 |
15 | 4c9b96293 |
hex | 2e3e2b575 |
12413220213 has 4 divisors (see below), whose sum is σ = 16550960288. Its totient is φ = 8275480140.
The previous prime is 12413220143. The next prime is 12413220257. The reversal of 12413220213 is 31202231421.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 12413220213 - 221 = 12411123061 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 12413220213.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12413220283) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2068870033 + ... + 2068870038.
It is an arithmetic number, because the mean of its divisors is an integer number (4137740072).
Almost surely, 212413220213 is an apocalyptic number.
It is an amenable number.
12413220213 is a deficient number, since it is larger than the sum of its proper divisors (4137740075).
12413220213 is an equidigital number, since it uses as much as digits as its factorization.
12413220213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4137740074.
The product of its (nonzero) digits is 576, while the sum is 21.
Adding to 12413220213 its reverse (31202231421), we get a palindrome (43615451634).
The spelling of 12413220213 in words is "twelve billion, four hundred thirteen million, two hundred twenty thousand, two hundred thirteen".
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