Base | Representation |
---|---|
bin | 111001110011101100… |
… | …1100010001111011011 |
3 | 102212102121210012201210 |
4 | 1303213121202033123 |
5 | 4013220134040120 |
6 | 133010231114203 |
7 | 11653223524113 |
oct | 1634731421733 |
9 | 385377705653 |
10 | 124141315035 |
11 | 48714599431 |
12 | 20086812963 |
13 | b92518683a |
14 | 6019364043 |
15 | 3368841ce0 |
hex | 1ce76623db |
124141315035 has 16 divisors (see below), whose sum is σ = 199304015904. Its totient is φ = 65982730752.
The previous prime is 124141315013. The next prime is 124141315043. The reversal of 124141315035 is 530513141421.
It is not a de Polignac number, because 124141315035 - 27 = 124141314907 is a prime.
It is a super-2 number, since 2×1241413150352 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 124141314993 and 124141315011.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14118622 + ... + 14127411.
It is an arithmetic number, because the mean of its divisors is an integer number (12456500994).
Almost surely, 2124141315035 is an apocalyptic number.
124141315035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
124141315035 is a deficient number, since it is larger than the sum of its proper divisors (75162700869).
124141315035 is a wasteful number, since it uses less digits than its factorization.
124141315035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28246334.
The product of its (nonzero) digits is 7200, while the sum is 30.
Adding to 124141315035 its reverse (530513141421), we get a palindrome (654654456456).
The spelling of 124141315035 in words is "one hundred twenty-four billion, one hundred forty-one million, three hundred fifteen thousand, thirty-five".
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