124143044311341 has 72 divisors (see below), whose sum is σ = 207660842057760. Its totient is φ = 71214477428160.

The previous prime is 124143044311339. The next prime is 124143044311453. The reversal of 124143044311341 is 143113440341421.

124143044311341 is a `hidden beast` number, since 1 + 2 + 4 + 1 + 4 + 304 + 4 + 3 + 1 + 1 + 341 = 666.

It is not a de Polignac number, because 124143044311341 - 2¹ = 124143044311339 is a prime.

It is a super-2 number, since 2×124143044311341² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 124143044311296 and 124143044311305.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (124143044311841) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 20426146 + ... + 25797548.

Almost surely, 2^{124143044311341} is an apocalyptic number.

124143044311341 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

124143044311341 is a deficient number, since it is larger than the sum of its proper divisors (83517797746419).

124143044311341 is a wasteful number, since it uses less digits than its factorization.

124143044311341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5372567 (or 5372553 counting only the distinct ones).

The product of its (nonzero) digits is 55296, while the sum is 36.

Adding to 124143044311341 its reverse (143113440341421), we get a palindrome (267256484652762).

The spelling of 124143044311341 in words is "one hundred twenty-four trillion, one hundred forty-three billion, forty-four million, three hundred eleven thousand, three hundred forty-one".