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12414604216551 = 34138201405517
BaseRepresentation
bin1011010010101000000000…
…0100110000100011100111
31121221211021010001112122120
42310222000010300203213
53111400102134412201
642223105045201023
72420632315502235
oct264520004604347
947854233045576
1012414604216551
113a57005483259
121486049a00173
136c08cc880984
1430cc275bb955
15167deb9ee536
hexb4a801308e7

12414604216551 has 4 divisors (see below), whose sum is σ = 16552805622072. Its totient is φ = 8276402811032.

The previous prime is 12414604216541. The next prime is 12414604216579. The reversal of 12414604216551 is 15561240641421.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12414604216551 - 213 = 12414604208359 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12414604216541) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2069100702756 + ... + 2069100702761.

It is an arithmetic number, because the mean of its divisors is an integer number (4138201405518).

Almost surely, 212414604216551 is an apocalyptic number.

12414604216551 is a deficient number, since it is larger than the sum of its proper divisors (4138201405521).

12414604216551 is an equidigital number, since it uses as much as digits as its factorization.

12414604216551 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4138201405520.

The product of its (nonzero) digits is 230400, while the sum is 42.

Adding to 12414604216551 its reverse (15561240641421), we get a palindrome (27975844857972).

The spelling of 12414604216551 in words is "twelve trillion, four hundred fourteen billion, six hundred four million, two hundred sixteen thousand, five hundred fifty-one".

Divisors: 1 3 4138201405517 12414604216551