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1242052300013 = 7177436042859
BaseRepresentation
bin10010000100110000000…
…101100000110011101101
311101201221202112021211112
4102010300011200303231
5130322210342100023
62350331351201405
7155510133232550
oct22046005406355
94351852467745
101242052300013
1143982a163548
12180874976265
13901818c6875
14441894c6697
1522496966478
hex12130160ced

1242052300013 has 4 divisors (see below), whose sum is σ = 1419488342880. Its totient is φ = 1064616257148.

The previous prime is 1242052300009. The next prime is 1242052300019. The reversal of 1242052300013 is 3100032502421.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1242052300013 - 22 = 1242052300009 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1242052300019) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 88718021423 + ... + 88718021436.

It is an arithmetic number, because the mean of its divisors is an integer number (354872085720).

Almost surely, 21242052300013 is an apocalyptic number.

It is an amenable number.

1242052300013 is a deficient number, since it is larger than the sum of its proper divisors (177436042867).

1242052300013 is an equidigital number, since it uses as much as digits as its factorization.

1242052300013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 177436042866.

The product of its (nonzero) digits is 1440, while the sum is 23.

Adding to 1242052300013 its reverse (3100032502421), we get a palindrome (4342084802434).

The spelling of 1242052300013 in words is "one trillion, two hundred forty-two billion, fifty-two million, three hundred thousand, thirteen".

Divisors: 1 7 177436042859 1242052300013