12421424113 has 4 divisors (see below), whose sum is σ = 14195913280. Its totient is φ = 10646934948.

The previous prime is 12421424111. The next prime is 12421424123. The reversal of 12421424113 is 31142412421.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12421424113 - 2¹ = 12421424111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12421424111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 887244573 + ... + 887244586.

It is an arithmetic number, because the mean of its divisors is an integer number (3548978320).

Almost surely, 2^12421424113 is an apocalyptic number.

It is an amenable number.

12421424113 is a deficient number, since it is larger than the sum of its proper divisors (1774489167).

12421424113 is an equidigital number, since it uses as much as digits as its factorization.

12421424113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1774489166.

The product of its digits is 1536, while the sum is 25.

Adding to 12421424113 its reverse (31142412421), we get a palindrome (43563836534).

The spelling of 12421424113 in words is "twelve billion, four hundred twenty-one million, four hundred twenty-four thousand, one hundred thirteen".