Base | Representation |
---|---|
bin | 1011010011001011110100… |
… | …1110001100000110011001 |
3 | 1121222202002020220122121120 |
4 | 2310302331032030012121 |
5 | 3112024300312032213 |
6 | 42231335145355453 |
7 | 2421422516546625 |
oct | 264627516140631 |
9 | 47882066818546 |
10 | 12424220033433 |
11 | 3a6009a34585a |
12 | 1487a92198b89 |
13 | 6c17a2aa6c50 |
14 | 30d49a6d6185 |
15 | 1682b0cc0423 |
hex | b4cbd38c199 |
12424220033433 has 64 divisors (see below), whose sum is σ = 18578172420864. Its totient is φ = 7335507456000.
The previous prime is 12424220033413. The next prime is 12424220033437. The reversal of 12424220033433 is 33433002242421.
12424220033433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 12424220033433 - 218 = 12424219771289 is a prime.
It is a super-2 number, since 2×124242200334332 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12424220033394 and 12424220033403.
It is not an unprimeable number, because it can be changed into a prime (12424220033437) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 739044598 + ... + 739061408.
It is an arithmetic number, because the mean of its divisors is an integer number (290283944076).
Almost surely, 212424220033433 is an apocalyptic number.
12424220033433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
12424220033433 is a deficient number, since it is larger than the sum of its proper divisors (6153952387431).
12424220033433 is a wasteful number, since it uses less digits than its factorization.
12424220033433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24506.
The product of its (nonzero) digits is 82944, while the sum is 33.
Adding to 12424220033433 its reverse (33433002242421), we get a palindrome (45857222275854).
The spelling of 12424220033433 in words is "twelve trillion, four hundred twenty-four billion, two hundred twenty million, thirty-three thousand, four hundred thirty-three".
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