124301540113 has 4 divisors (see below), whose sum is σ = 127192273648. Its totient is φ = 121410806580.

The previous prime is 124301540021. The next prime is 124301540119. The reversal of 124301540113 is 311045103421.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-124301540113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (124301540119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1445366703 + ... + 1445366788.

It is an arithmetic number, because the mean of its divisors is an integer number (31798068412).

Almost surely, 2^124301540113 is an apocalyptic number.

It is an amenable number.

124301540113 is a deficient number, since it is larger than the sum of its proper divisors (2890733535).

124301540113 is an equidigital number, since it uses as much as digits as its factorization.

124301540113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2890733534.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 124301540113 its reverse (311045103421), we get a palindrome (435346643534).

The spelling of 124301540113 in words is "one hundred twenty-four billion, three hundred one million, five hundred forty thousand, one hundred thirteen".