124331135141 has 4 divisors (see below), whose sum is σ = 124336646784. Its totient is φ = 124325623500.

The previous prime is 124331135129. The next prime is 124331135143. The reversal of 124331135141 is 141531133421.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 141531133421 = 12517 ⋅11307113.

It is a cyclic number.

It is not a de Polignac number, because 124331135141 - 2¹⁰ = 124331134117 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (124331135143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2721845 + ... + 2767146.

It is an arithmetic number, because the mean of its divisors is an integer number (31084161696).

Almost surely, 2^124331135141 is an apocalyptic number.

It is an amenable number.

124331135141 is a deficient number, since it is larger than the sum of its proper divisors (5511643).

124331135141 is an equidigital number, since it uses as much as digits as its factorization.

124331135141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5511642.

The product of its digits is 4320, while the sum is 29.

Adding to 124331135141 its reverse (141531133421), we get a palindrome (265862268562).

The spelling of 124331135141 in words is "one hundred twenty-four billion, three hundred thirty-one million, one hundred thirty-five thousand, one hundred forty-one".