Base | Representation |
---|---|
bin | 10111001010001010… |
… | …10010101000110001 |
3 | 1012002111110021211221 |
4 | 23211011102220301 |
5 | 200430411212423 |
6 | 5413424505041 |
7 | 620052225016 |
oct | 134505225061 |
9 | 35074407757 |
10 | 12433304113 |
11 | 530030444a |
12 | 24aba7b181 |
13 | 1231b66ca9 |
14 | 85d3b170d |
15 | 4cb811e5d |
hex | 2e5152a31 |
12433304113 has 8 divisors (see below), whose sum is σ = 13090452800. Its totient is φ = 11776431888.
The previous prime is 12433304111. The next prime is 12433304119. The reversal of 12433304113 is 31140333421.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 12433304113 - 21 = 12433304111 is a prime.
It is not an unprimeable number, because it can be changed into a prime (12433304111) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 26620 + ... + 159922.
It is an arithmetic number, because the mean of its divisors is an integer number (1636306600).
Almost surely, 212433304113 is an apocalyptic number.
It is an amenable number.
12433304113 is a deficient number, since it is larger than the sum of its proper divisors (657148687).
12433304113 is a wasteful number, since it uses less digits than its factorization.
12433304113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 138231.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 12433304113 its reverse (31140333421), we get a palindrome (43573637534).
The spelling of 12433304113 in words is "twelve billion, four hundred thirty-three million, three hundred four thousand, one hundred thirteen".
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