Base | Representation |
---|---|
bin | 10111001010010010… |
… | …00110110101010111 |
3 | 1012002120100002220111 |
4 | 23211021012311113 |
5 | 200431140214333 |
6 | 5413502143451 |
7 | 620063562106 |
oct | 134511066527 |
9 | 35076302814 |
10 | 12434304343 |
11 | 530092798a |
12 | 24b0281b87 |
13 | 1232127346 |
14 | 85d59203d |
15 | 4cb95d4cd |
hex | 2e5246d57 |
12434304343 has 4 divisors (see below), whose sum is σ = 12517756200. Its totient is φ = 12350852488.
The previous prime is 12434304341. The next prime is 12434304347. The reversal of 12434304343 is 34340343421.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12434304343 - 21 = 12434304341 is a prime.
It is a super-2 number, since 2×124343043432 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12434304341) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41725705 + ... + 41726002.
It is an arithmetic number, because the mean of its divisors is an integer number (3129439050).
Almost surely, 212434304343 is an apocalyptic number.
12434304343 is a deficient number, since it is larger than the sum of its proper divisors (83451857).
12434304343 is an equidigital number, since it uses as much as digits as its factorization.
12434304343 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 83451856.
The product of its (nonzero) digits is 41472, while the sum is 31.
Adding to 12434304343 its reverse (34340343421), we get a palindrome (46774647764).
The spelling of 12434304343 in words is "twelve billion, four hundred thirty-four million, three hundred four thousand, three hundred forty-three".
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