Base | Representation |
---|---|
bin | 11100010001011011101000… |
… | …010110011111100111110010 |
3 | 121022021002112111111210110202 |
4 | 130101123220112133213302 |
5 | 112244214334031230002 |
6 | 1120242251140355202 |
7 | 35122333306210622 |
oct | 3421335026374762 |
9 | 538232474453422 |
10 | 124343201430002 |
11 | 3668a72364a935 |
12 | 11b426666a5b02 |
13 | 544c68a455c29 |
14 | 229c358d5a882 |
15 | e596ba888502 |
hex | 7116e859f9f2 |
124343201430002 has 4 divisors (see below), whose sum is σ = 186514802145006. Its totient is φ = 62171600715000.
The previous prime is 124343201429999. The next prime is 124343201430023. The reversal of 124343201430002 is 200034102343421.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 114526190259481 + 9817011170521 = 10701691^2 + 3133211^2 .
It is a super-2 number, since 2×1243432014300022 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 31085800357499 + ... + 31085800357502.
Almost surely, 2124343201430002 is an apocalyptic number.
124343201430002 is a deficient number, since it is larger than the sum of its proper divisors (62171600715004).
124343201430002 is an equidigital number, since it uses as much as digits as its factorization.
124343201430002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 62171600715003.
The product of its (nonzero) digits is 13824, while the sum is 29.
Adding to 124343201430002 its reverse (200034102343421), we get a palindrome (324377303773423).
The spelling of 124343201430002 in words is "one hundred twenty-four trillion, three hundred forty-three billion, two hundred one million, four hundred thirty thousand, two".
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