12434444113 has 64 divisors (see below), whose sum is σ = 17113904640. Its totient is φ = 8742961152.

The previous prime is 12434444081. The next prime is 12434444137. The reversal of 12434444113 is 31144443421.

12434444113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a cyclic number.

It is not a de Polignac number, because 12434444113 - 2⁵ = 12434444081 is a prime.

It is not an unprimeable number, because it can be changed into a prime (12434442113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 12726681 + ... + 12727657.

It is an arithmetic number, because the mean of its divisors is an integer number (267404760).

Almost surely, 2^12434444113 is an apocalyptic number.

12434444113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

12434444113 is a deficient number, since it is larger than the sum of its proper divisors (4679460527).

12434444113 is a wasteful number, since it uses less digits than its factorization.

12434444113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1466.

The product of its digits is 18432, while the sum is 31.

Adding to 12434444113 its reverse (31144443421), we get a palindrome (43578887534).

The spelling of 12434444113 in words is "twelve billion, four hundred thirty-four million, four hundred forty-four thousand, one hundred thirteen".