12440434333 has 4 divisors (see below), whose sum is σ = 12590319168. Its totient is φ = 12290549500.

The previous prime is 12440434309. The next prime is 12440434417. The reversal of 12440434333 is 33343404421.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12440434333 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12440434295 and 12440434304.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12440434933) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 74942293 + ... + 74942458.

It is an arithmetic number, because the mean of its divisors is an integer number (3147579792).

Almost surely, 2^12440434333 is an apocalyptic number.

It is an amenable number.

12440434333 is a deficient number, since it is larger than the sum of its proper divisors (149884835).

12440434333 is an equidigital number, since it uses as much as digits as its factorization.

12440434333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 149884834.

The product of its (nonzero) digits is 41472, while the sum is 31.

Adding to 12440434333 its reverse (33343404421), we get a palindrome (45783838754).

The spelling of 12440434333 in words is "twelve billion, four hundred forty million, four hundred thirty-four thousand, three hundred thirty-three".