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12443204113 = 14983511437
BaseRepresentation
bin10111001011010110…
…00011101000010001
31012010012002021002121
423211223003220101
5200440430012423
65414421014241
7620232330004
oct134553035021
935105067077
1012443204113
11530595646a
1224b3254381
131233c22192
1486082b53b
154cc61a45d
hex2e5ac3a11

12443204113 has 4 divisors (see below), whose sum is σ = 12526715700. Its totient is φ = 12359692528.

The previous prime is 12443204071. The next prime is 12443204129. The reversal of 12443204113 is 31140234421.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6141543424 + 6301660689 = 78368^2 + 79383^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12443204113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12443204413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41755570 + ... + 41755867.

It is an arithmetic number, because the mean of its divisors is an integer number (3131678925).

Almost surely, 212443204113 is an apocalyptic number.

It is an amenable number.

12443204113 is a deficient number, since it is larger than the sum of its proper divisors (83511587).

12443204113 is an equidigital number, since it uses as much as digits as its factorization.

12443204113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 83511586.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 12443204113 its reverse (31140234421), we get a palindrome (43583438534).

The spelling of 12443204113 in words is "twelve billion, four hundred forty-three million, two hundred four thousand, one hundred thirteen".

Divisors: 1 149 83511437 12443204113