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1244331005141 = 735413670199
BaseRepresentation
bin10010000110110111111…
…010000101010011010101
311101221211120022111121202
4102012313322011103111
5130341342214131031
62351345431522245
7155620453013000
oct22066772052325
94357746274552
101244331005141
1143a79945a424
121811abb29385
1390455a240b3
1444323db0537
152257ba2d2cb
hex121b7e854d5

1244331005141 has 16 divisors (see below), whose sum is σ = 1451385120000. Its totient is φ = 1066370803344.

The previous prime is 1244331005131. The next prime is 1244331005293. The reversal of 1244331005141 is 1415001334421.

It is not a de Polignac number, because 1244331005141 - 210 = 1244331004117 is a prime.

It is a super-2 number, since 2×12443310051412 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1244331005101) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1521560 + ... + 2191758.

It is an arithmetic number, because the mean of its divisors is an integer number (90711570000).

Almost surely, 21244331005141 is an apocalyptic number.

It is an amenable number.

1244331005141 is a deficient number, since it is larger than the sum of its proper divisors (207054114859).

1244331005141 is an frugal number, since it uses more digits than its factorization.

1244331005141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 675633 (or 675619 counting only the distinct ones).

The product of its (nonzero) digits is 5760, while the sum is 29.

Adding to 1244331005141 its reverse (1415001334421), we get a palindrome (2659332339562).

The spelling of 1244331005141 in words is "one trillion, two hundred forty-four billion, three hundred thirty-one million, five thousand, one hundred forty-one".

Divisors: 1 7 49 343 5413 37891 265237 670199 1856659 4691393 32839751 229878257 3627787187 25394510309 177761572163 1244331005141