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12443475541253 = 51755324042901
BaseRepresentation
bin1011010100010011100011…
…1100000111110100000101
31122001120210012112210120212
42311010320330013310011
53112333214214310003
642244242002005205
72423003631634451
oct265047074076405
948046705483525
1012443475541253
113a682805a6889
12148b766946805
136c3551165063
143103a5b81661
15168a3b4cadd8
hexb5138f07d05

12443475541253 has 4 divisors (see below), whose sum is σ = 12443500101708. Its totient is φ = 12443450980800.

The previous prime is 12443475541223. The next prime is 12443475541271. The reversal of 12443475541253 is 35214557434421.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 7218260169124 + 5225215372129 = 2686682^2 + 2285873^2 .

It is a cyclic number.

It is not a de Polignac number, because 12443475541253 - 28 = 12443475540997 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12443475541223) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11503898 + ... + 12539003.

It is an arithmetic number, because the mean of its divisors is an integer number (3110875025427).

Almost surely, 212443475541253 is an apocalyptic number.

It is an amenable number.

12443475541253 is a deficient number, since it is larger than the sum of its proper divisors (24560455).

12443475541253 is an equidigital number, since it uses as much as digits as its factorization.

12443475541253 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24560454.

The product of its digits is 8064000, while the sum is 50.

The spelling of 12443475541253 in words is "twelve trillion, four hundred forty-three billion, four hundred seventy-five million, five hundred forty-one thousand, two hundred fifty-three".

Divisors: 1 517553 24042901 12443475541253