Base | Representation |
---|---|
bin | 10010000110111100110… |
… | …011011010110001010111 |
3 | 11101222001021212121011022 |
4 | 102012330303122301113 |
5 | 130342024231103101 |
6 | 2351401524231355 |
7 | 155622501125222 |
oct | 22067463326127 |
9 | 4358037777138 |
10 | 1244413144151 |
11 | 43a830861701 |
12 | 18121353b55b |
13 | 90469a52c68 |
14 | 44330c725b9 |
15 | 22583d55a1b |
hex | 121bccdac57 |
1244413144151 has 4 divisors (see below), whose sum is σ = 1258395314400. Its totient is φ = 1230430973904.
The previous prime is 1244413144099. The next prime is 1244413144171. The reversal of 1244413144151 is 1514413144421.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1244413144151 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1244413144171) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6991084991 + ... + 6991085168.
It is an arithmetic number, because the mean of its divisors is an integer number (314598828600).
Almost surely, 21244413144151 is an apocalyptic number.
1244413144151 is a deficient number, since it is larger than the sum of its proper divisors (13982170249).
1244413144151 is an equidigital number, since it uses as much as digits as its factorization.
1244413144151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13982170248.
The product of its digits is 30720, while the sum is 35.
Adding to 1244413144151 its reverse (1514413144421), we get a palindrome (2758826288572).
The spelling of 1244413144151 in words is "one trillion, two hundred forty-four billion, four hundred thirteen million, one hundred forty-four thousand, one hundred fifty-one".
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