Base | Representation |
---|---|
bin | 1011010100101100111111… |
… | …1010011110011001111101 |
3 | 1122002020102001102210220210 |
4 | 2311023033322132121331 |
5 | 3112441210134431123 |
6 | 42251331311303033 |
7 | 2423335061040363 |
oct | 265131772363175 |
9 | 48066361383823 |
10 | 12450303436413 |
11 | 3a70164790547 |
12 | 1490b5151aa79 |
13 | 6c409b8cc8cb |
14 | 3108528db633 |
15 | 168cdab4ae93 |
hex | b52cfe9e67d |
12450303436413 has 4 divisors (see below), whose sum is σ = 16600404581888. Its totient is φ = 8300202290940.
The previous prime is 12450303436391. The next prime is 12450303436453. The reversal of 12450303436413 is 31463430305421.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 12450303436413 - 26 = 12450303436349 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12450303436453) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2075050572733 + ... + 2075050572738.
It is an arithmetic number, because the mean of its divisors is an integer number (4150101145472).
Almost surely, 212450303436413 is an apocalyptic number.
It is an amenable number.
12450303436413 is a deficient number, since it is larger than the sum of its proper divisors (4150101145475).
12450303436413 is an equidigital number, since it uses as much as digits as its factorization.
12450303436413 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4150101145474.
The product of its (nonzero) digits is 311040, while the sum is 39.
The spelling of 12450303436413 in words is "twelve trillion, four hundred fifty billion, three hundred three million, four hundred thirty-six thousand, four hundred thirteen".
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