12451204015441 has 4 divisors (see below), whose sum is σ = 12497149417984. Its totient is φ = 12405258612900.

The previous prime is 12451204015409. The next prime is 12451204015519. The reversal of 12451204015441 is 14451040215421.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12451204015441 - 2⁵ = 12451204015409 is a prime.

It is a super-3 number, since 3×12451204015441³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12451204015397 and 12451204015406.

It is not an unprimeable number, because it can be changed into a prime (12451204018441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22972700865 + ... + 22972701406.

It is an arithmetic number, because the mean of its divisors is an integer number (3124287354496).

Almost surely, 2^{12451204015441} is an apocalyptic number.

It is an amenable number.

12451204015441 is a deficient number, since it is larger than the sum of its proper divisors (45945402543).

12451204015441 is an equidigital number, since it uses as much as digits as its factorization.

12451204015441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 45945402542.

The product of its (nonzero) digits is 25600, while the sum is 34.

The spelling of 12451204015441 in words is "twelve trillion, four hundred fifty-one billion, two hundred four million, fifteen thousand, four hundred forty-one".