Base | Representation |
---|---|
bin | 1011010101111101011100… |
… | …1101100010110000000111 |
3 | 1122011022011012112002021111 |
4 | 2311133113031202300013 |
5 | 3113314423040240233 |
6 | 42305302340025451 |
7 | 2425031216616301 |
oct | 265372715426007 |
9 | 48138135462244 |
10 | 12471900711943 |
11 | 3a793378a0292 |
12 | 149517a392287 |
13 | 6c613119819a |
14 | 311900da8971 |
15 | 169651c28acd |
hex | b57d7362c07 |
12471900711943 has 4 divisors (see below), whose sum is σ = 12472003438128. Its totient is φ = 12471797985760.
The previous prime is 12471900711871. The next prime is 12471900711953. The reversal of 12471900711943 is 34911700917421.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12471900711943 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12471900711953) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51180763 + ... + 51423868.
It is an arithmetic number, because the mean of its divisors is an integer number (3118000859532).
Almost surely, 212471900711943 is an apocalyptic number.
12471900711943 is a deficient number, since it is larger than the sum of its proper divisors (102726185).
12471900711943 is a wasteful number, since it uses less digits than its factorization.
12471900711943 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 102726184.
The product of its (nonzero) digits is 381024, while the sum is 49.
The spelling of 12471900711943 in words is "twelve trillion, four hundred seventy-one billion, nine hundred million, seven hundred eleven thousand, nine hundred forty-three".
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