Base | Representation |
---|---|
bin | 1011010111100110101000… |
… | …0011000000100110101101 |
3 | 1122021000000211102222120020 |
4 | 2311321222003000212231 |
5 | 3114300233301131130 |
6 | 42330252101312353 |
7 | 2430050654633442 |
oct | 265715203004655 |
9 | 48230024388506 |
10 | 12500134005165 |
11 | 3a8a30584a374 |
12 | 149a7397056b9 |
13 | 6c89b0529151 |
14 | 31301c9259c9 |
15 | 16a2556c3e10 |
hex | b5e6a0c09ad |
12500134005165 has 8 divisors (see below), whose sum is σ = 20000214408288. Its totient is φ = 6666738136080.
The previous prime is 12500134005157. The next prime is 12500134005187. The reversal of 12500134005165 is 56150043100521.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 12500134005165 - 23 = 12500134005157 is a prime.
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 416671133491 + ... + 416671133520.
It is an arithmetic number, because the mean of its divisors is an integer number (2500026801036).
Almost surely, 212500134005165 is an apocalyptic number.
12500134005165 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
12500134005165 is a deficient number, since it is larger than the sum of its proper divisors (7500080403123).
12500134005165 is an equidigital number, since it uses as much as digits as its factorization.
12500134005165 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 833342267019.
The product of its (nonzero) digits is 18000, while the sum is 33.
Adding to 12500134005165 its reverse (56150043100521), we get a palindrome (68650177105686).
The spelling of 12500134005165 in words is "twelve trillion, five hundred billion, one hundred thirty-four million, five thousand, one hundred sixty-five".
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