Base | Representation |
---|---|
bin | 111010001101010110… |
… | …1010011001010001001 |
3 | 102221122121120100120100 |
4 | 1310122231103022021 |
5 | 4022001021243103 |
6 | 133231501320013 |
7 | 12013445415621 |
oct | 1643255231211 |
9 | 387577510510 |
10 | 125002134153 |
11 | 4901649a596 |
12 | 20286b66009 |
13 | ba31612470 |
14 | 609b801881 |
15 | 33b91ce5a3 |
hex | 1d1ab53289 |
125002134153 has 24 divisors (see below), whose sum is σ = 195735525440. Its totient is φ = 76414946400.
The previous prime is 125002134143. The next prime is 125002134163. The reversal of 125002134153 is 351431200521.
125002134153 is a `hidden beast` number, since 1 + 2 + 500 + 2 + 1 + 3 + 4 + 153 = 666.
It is an interprime number because it is at equal distance from previous prime (125002134143) and next prime (125002134163).
It is not a de Polignac number, because 125002134153 - 24 = 125002134137 is a prime.
It is not an unprimeable number, because it can be changed into a prime (125002134133) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3520063 + ... + 3555396.
Almost surely, 2125002134153 is an apocalyptic number.
125002134153 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
125002134153 is a deficient number, since it is larger than the sum of its proper divisors (70733391287).
125002134153 is a wasteful number, since it uses less digits than its factorization.
125002134153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7075629 (or 7075626 counting only the distinct ones).
The product of its (nonzero) digits is 3600, while the sum is 27.
Adding to 125002134153 its reverse (351431200521), we get a palindrome (476433334674).
The spelling of 125002134153 in words is "one hundred twenty-five billion, two million, one hundred thirty-four thousand, one hundred fifty-three".
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