12500310025 has 12 divisors (see below), whose sum is σ = 17714725312. Its totient is φ = 8571641040.

The previous prime is 12500310023. The next prime is 12500310059. The reversal of 12500310025 is 52001300521.

It is not a de Polignac number, because 12500310025 - 2¹ = 12500310023 is a prime.

It is a super-3 number, since 3×12500310025³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12500309984 and 12500310011.

It is not an unprimeable number, because it can be changed into a prime (12500310023) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 35714997 + ... + 35715346.

Almost surely, 2^12500310025 is an apocalyptic number.

It is an amenable number.

12500310025 is a deficient number, since it is larger than the sum of its proper divisors (5214415287).

12500310025 is an equidigital number, since it uses as much as digits as its factorization.

12500310025 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 71430360 (or 71430355 counting only the distinct ones).

The product of its (nonzero) digits is 300, while the sum is 19.

Adding to 12500310025 its reverse (52001300521), we get a palindrome (64501610546).

The spelling of 12500310025 in words is "twelve billion, five hundred million, three hundred ten thousand, twenty-five".