Base | Representation |
---|---|
bin | 11100011011000010010100… |
… | …000000011111100101110001 |
3 | 121101121012010201121010212112 |
4 | 130123002110000133211301 |
5 | 112341023034100341040 |
6 | 1121505403231335105 |
7 | 35221120051660115 |
oct | 3433022400374561 |
9 | 541535121533775 |
10 | 125003211340145 |
11 | 36914622a7a096 |
12 | 1202a562681495 |
13 | 54999a19002b8 |
14 | 22c228b113745 |
15 | e6b948c65365 |
hex | 71b09401f971 |
125003211340145 has 16 divisors (see below), whose sum is σ = 153494151370560. Its totient is φ = 97675759535424.
The previous prime is 125003211340141. The next prime is 125003211340171. The reversal of 125003211340145 is 541043112300521.
It is a cyclic number.
It is not a de Polignac number, because 125003211340145 - 22 = 125003211340141 is a prime.
It is not an unprimeable number, because it can be changed into a prime (125003211340141) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14760182 + ... + 21630288.
It is an arithmetic number, because the mean of its divisors is an integer number (9593384460660).
Almost surely, 2125003211340145 is an apocalyptic number.
It is an amenable number.
125003211340145 is a deficient number, since it is larger than the sum of its proper divisors (28490940030415).
125003211340145 is an equidigital number, since it uses as much as digits as its factorization.
125003211340145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6954784.
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 125003211340145 its reverse (541043112300521), we get a palindrome (666046323640666).
The spelling of 125003211340145 in words is "one hundred twenty-five trillion, three billion, two hundred eleven million, three hundred forty thousand, one hundred forty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.083 sec. • engine limits •