Base | Representation |
---|---|
bin | 10010001100001100111… |
… | …110101000111010101111 |
3 | 11102111121100200122210020 |
4 | 102030030332220322233 |
5 | 130440102111332010 |
6 | 2354133323013223 |
7 | 156212325066024 |
oct | 22141476507257 |
9 | 4374540618706 |
10 | 1250053230255 |
11 | 442165506895 |
12 | 18232836a213 |
13 | 90b583a420b |
14 | 44707d5354b |
15 | 227b4097470 |
hex | 1230cfa8eaf |
1250053230255 has 16 divisors (see below), whose sum is σ = 2013508562400. Its totient is φ = 662220591488.
The previous prime is 1250053230253. The next prime is 1250053230277. The reversal of 1250053230255 is 5520323500521.
It is a cyclic number.
It is not a de Polignac number, because 1250053230255 - 21 = 1250053230253 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1250053230253) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 279651732 + ... + 279656201.
It is an arithmetic number, because the mean of its divisors is an integer number (125844285150).
Almost surely, 21250053230255 is an apocalyptic number.
1250053230255 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1250053230255 is a deficient number, since it is larger than the sum of its proper divisors (763455332145).
1250053230255 is a wasteful number, since it uses less digits than its factorization.
1250053230255 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 559308090.
The product of its (nonzero) digits is 45000, while the sum is 33.
Adding to 1250053230255 its reverse (5520323500521), we get a palindrome (6770376730776).
The spelling of 1250053230255 in words is "one trillion, two hundred fifty billion, fifty-three million, two hundred thirty thousand, two hundred fifty-five".
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