12501043113101 has 4 divisors (see below), whose sum is σ = 12501051508704. Its totient is φ = 12501034717500.

The previous prime is 12501043113079. The next prime is 12501043113103. The reversal of 12501043113101 is 10131134010521.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12501043113101 is a prime.

It is a super-4 number, since 4×12501043113101⁴ (a number of 53 digits) contains 4444 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12501043113103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1295375 + ... + 5165276.

It is an arithmetic number, because the mean of its divisors is an integer number (3125262877176).

Almost surely, 2^{12501043113101} is an apocalyptic number.

It is an amenable number.

12501043113101 is a deficient number, since it is larger than the sum of its proper divisors (8395603).

12501043113101 is an equidigital number, since it uses as much as digits as its factorization.

12501043113101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8395602.

The product of its (nonzero) digits is 360, while the sum is 23.

Adding to 12501043113101 its reverse (10131134010521), we get a palindrome (22632177123622).

The spelling of 12501043113101 in words is "twelve trillion, five hundred one billion, forty-three million, one hundred thirteen thousand, one hundred one".