1250242053133 has 4 divisors (see below), whose sum is σ = 1280735761788. Its totient is φ = 1219748344480.

The previous prime is 1250242053131. The next prime is 1250242053139. The reversal of 1250242053133 is 3313502420521.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 72415886404 + 1177826166729 = 269102^2 + 1085277^2 .

It is a cyclic number.

It is not a de Polignac number, because 1250242053133 - 2¹ = 1250242053131 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1250242053095 and 1250242053104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1250242053131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15246854266 + ... + 15246854347.

It is an arithmetic number, because the mean of its divisors is an integer number (320183940447).

Almost surely, 2^{1250242053133} is an apocalyptic number.

It is an amenable number.

1250242053133 is a deficient number, since it is larger than the sum of its proper divisors (30493708655).

1250242053133 is an equidigital number, since it uses as much as digits as its factorization.

1250242053133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30493708654.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 1250242053133 its reverse (3313502420521), we get a palindrome (4563744473654).

The spelling of 1250242053133 in words is "one trillion, two hundred fifty billion, two hundred forty-two million, fifty-three thousand, one hundred thirty-three".